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Uncut Full Movie Download Fast And Furious 6 In Tamil. Watch Download Hindi Indian 720p Dual Audio 480p 480p BluRay mp3 Mp4 Fast And Furious 6 2013 HD Indian Dubbed Audio Watch Online Download English Hindi Tamil.. To listen and download from the original subtitle file in. Fast and Furious .Q: Is this integral of a step function well-defined? In the end of page 595 of S.O. – Elementary Calculus – 3rd edition by P. Fife, a book I’m using, he has proved that the integral of a step function is independent of the step. Here is his proof: Proof. Suppose $f(x)$ is defined in $[a,b]$. Let $a=x_0 \alpha_{k+1}$ for $k=1,\cdots, n-1$. Now, $$\int_a^b f(x)dx=\sum_{k=0}^{n-1}f(x_k)(x_{k+1}-x_k)=\sum_{k=0}^{n-1} \alpha_{k+1}(x_{k+1}-x_k).$$ Now, suppose $f(x)$ is a step function. Let $h>0$ and $g(t)=f(x-h)+f(x+h)$ with $x-h<x<x+h$. Let $\alpha=\alpha_k$ and $\beta=\alpha_{k+1}$. Then, $$\int_{\alpha-h}^{\alpha+h}f(x)dx=\sum_{k=0}^{n-1}(\alpha+h-\alpha_k)(\alpha_{k+1}-\alpha_k)$$ and $$\int_{\beta-h}^{\beta+h}f(x)dx=\sum_{k=0}^{n-1}(\beta+h-\alpha_k)(\alpha_{k+1}-\alpha_k).$$ Thus, $$\int_{\alpha-h}^{\alpha+h}f(x)dx+\ f988f36e3a


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